[gambit-list] port fun

lowly coder lowlycoder at huoyanjinjing.com
Mon Oct 12 04:15:10 EDT 2009


Hi!

  I have some pre-existing library code I'm dealing with, which I can
pass it an port (that the library will send output to).

Is it possible to create a function foo, so that

(foo output-port1 output-port2)

will return me a output-port-magic

s.t. when anything iw written to output-port-magic, it's written to
both output-port1 and output-port2?

Thanks!


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